WebMar 23, 2024 · Transcript Example 1 Construct a triangle ABC, in which ∠B = 60°, ∠C = 45° and AB + BC + CA = 11 cm Given ∠B = 60°, ∠C = 45° and AB + BC + CA = 11 cm … WebDec 20, 2024 · 1. Draw the line segment you need to bisect. If the line segment is not already given, you will need to make it using a straightedge. 2. Choose an appropriately sized compass. If you open the compass completely, and it spans one-half the length of the line or less, you need to choose a bigger compass. [1]
Using the angle bisector theorem (video) Khan Academy
WebMar 25, 2024 · Draw a line segment AB of length 5.6 cm. Then construct another line segment PQ, double the length of AB. Find its measure. 2. Construct an angle of 60∘ with the help of a pair of compasses and a ruler. 3. Construct an angle of 120∘ with help of a protractor and bisect it by using a pair of compasses. 4. Construct a circle with centre … WebSteps of construction: To construct an angle of 135°. Draw an angle BOA = 90° at point O of given line AC. Bisect the angle BOC on the other side of OB, which is also 90°. Thus, ∠BOD = ∠COD = 45°. And, ∠AOD = 90° + 45° = 135°. Concept: Measure of Line Segment. chrome private browsing mode
Construct a triangle ABC, in which angle B = 60, C = 45 - teachoo
WebSep 25, 2024 · To Find : construct triangle Solution: Step 1: Draw a line segment BC 6 cm. Step 2 : Draw ∠B =60° using protractor and draw a ray BX. Step 3 : With Center B and … WebThen ∠OBC=90° 7. Construct BA, the bisector of angle OBC. [With D, L as centers and suitable radius construct two arc meeting each other at Q produced it to R] =>∠ABC=45°[∴BA is bisector of ∠OBC∴∠ABC==45°] 8. From BR cut arc AB = 4.6 cm Question 5. Construct angle ABC = 90°. Draw BP, the bisector of angle ABC. WebApr 28, 2024 · Considering P as the centre and radius more than half of the angle PQ, construct another arc which intersects the previous arc at the point R. Join the points OR and produce it in order to form a ray OX. Therefore, OX is the required bisector of the ∠AOB. So the measure of each part of the bisected angle is ∠AOX = ∠BOX = 40 o chrome private incognito window