Webb31 aug. 2024 · Calculate the pH of 0.1M CH3COOH solution. Dissociation constant of acetic acid is 1.8 x 10-5 ionic equilibrium class-12 1 Answer +2 votes answered Aug 31, 2024 by Nilam01 (35.8k points) selected Sep 1, 2024 by subnam02 pH = – log [H+] For weak acids, ← Prev Question Next Question → Find MCQs & Mock Test JEE Main 2024 … Webb29 nov. 2024 · Anaerobic digestion (AD) represents an advantageous solution for the treatment and valorization of organic waste and wastewater. To be suitable for energy purposes, biogas generated in AD must be subjected to proper upgrading treatments aimed at the removal of carbon dioxide and other undesirable gases. Pressurized anaerobic …
What is the pH of buffer solution of a 0.5M CH3COOH and 0.5m …
Webb18 okt. 2024 · Calculate the pH of a buffer solution containing 0.1 M CH 3 COOH and 0.05 M CH 3 COONa. Dissociation constant of CH 3 COOH is 1.8 × 10-5 at 25°C. WebbThe pH scale is a compact way to specify the acidity of a solution: pH = - log[H3O+] - Define the pH value of a solution: • Acidic solution: pH < 7 or [H3O ... we can use the equation to calculate the initial concentration of CH3COOH and CH3COONa when they are mixed together. We can assume that the volumes are additive, so the final volume is ... spanish name for prickly pear cactus
What is the pH of a 0.1 M solution of a strong base? - Quora
Webb1 dec. 2024 · Calculate the pH of a solution obtained by mixing 50 ml of 0.1 M NaOH with 100 ml of 0.1 M CH3COOH, Ka for CH3COOH = 1.8 x 10-5 ? LIVE Course for free. Rated by 1 million+ students Get app now Login. Remember. ... Calculate the pH of a solution obtained by mixing 50 ml of 0.1 M NaOH with 100 ml of 0.1 M CH 3 COOH, Ka for CH 3 COOH ... WebbBecause H 3 O + concentration is known now, pH value of acetic acid solution can be calculated. pH = -log[H 3 O + (aq)] pH = -log[1.34 * 10-3] pH = 2.88; pH Calculator of … WebbThe pH of 0.1M solution of CH 3COOH if it ionizes to an extent of 1 % is: A 1 B 2 C 3 D 4 Medium Solution Verified by Toppr Correct option is C) Acetic acid is 1 % ionized in aqueous solution. So, [H +]= 100percentage×concentration= 1001 ×0.1=1×10 −3 pH=−logH +=−log(1×10 −3)=3 Was this answer helpful? 0 0 Similar questions Assertion spanish name for sharon